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2x^2+47x-90=0
a = 2; b = 47; c = -90;
Δ = b2-4ac
Δ = 472-4·2·(-90)
Δ = 2929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{2929}}{2*2}=\frac{-47-\sqrt{2929}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{2929}}{2*2}=\frac{-47+\sqrt{2929}}{4} $
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